Math 470 Spring Õ05

HW #6 Solutions

 

Section 2.4

6. Assume that A satisfies the LHS.   Then either A does not satisfy Y or it satisfies $x j(x).  If the latter, there is an a in A such that A satisfies j(a). In either case, A satisfies Y v j(a).  So A satisfies $x(Y -> j(x)), which is the RHS.

Assume that A satisfies the RHS $x(Y -> j(x)). Then for some a in A, A satisfies Y v j(a).  Then A does not satisfy Y or it satisfies j(a).  If the latter, A satisfies $x j(x).  So in either case it satisfies Y -> $x j(x), which is the LHS.

If x is free in Y,  the LHS still implies the RHS but not conversely.  Take A to be the set of natural numbers, Y  to be x is even and j(x) to be x > x.

Then A satisfies the RHS, since 3 is even => 3 > 3. But A does not satisfy the LHS, which, universally quantified, says that is x is even there is a number y such that y > y.

7. Assume that A satisfies the LHS.   Then either A does not satisfy $x j(x) or it satisfies Y.  If the former then, no a in A satisfies j(a). In either case, every a in  A satisfies j(a) ->Y.  So A satisfies "x(j(x) -> Y), which is the RHS.

 

Assume that A satisfies the RHS "x(j(x) ->Y). Then every a in A satisfies  j(a) ->Y.    Then A does not satisfy j(a) or it satisfies Y.  If, A satisfies  j(a)  for any a, it satisfies Y. So A satisfies $x j(x) -> Y, which is the LHS.

If x is free in Y,  the LHS still implies the RHS but not conversely.  Take A as above, Y   to be x  is even and j(x) to be x is a multiple of 4.

Then A satisfies the RHS, since if x is a multiple of 4, it is even. But A does not satisfy the LHS, which, universally quantified, says that is if there is any multiple of 4, then every number is even.

 

Section 2.6

1. F (($x(j(x) v y(x)) <->  ($xj(x) v $xy(x))

              /                                         \

     T $x(j(x) v y(x))               F($x(j(x) v y(x))

     F ($xj(x) v $xy(x))          T ($xj(x) v $xy(x))

      T j(c) v y(c)                        /                    \

      F  ($xj(x))                        T($xj(x))     T$xy(x))

      F $x y(x)                            T y(d)           Ty(e)

       F j(c)                             F(j(d) v y(d))   F(j(e) v y(e))

        F y(c)                               F(j(d))               F(j(e)

        /      \                                   F(y(d))                F(y(e))

   Tj(c)   Ty(c)                            X                           X

     X         X

   

2. . F (("x(j(x) ^ y(x)) <->  ("xj(x) ^ "xy(x))

              /                                         \

     T "x(j(x) ^ y(x))               F("x(j(x) ^ y(x))

     F ("xj(x) ^ "xy(x))          T ("xj(x) ^ "xy(x))

        /                   \                         T "xj(x)

      F"xj(x)     F"xy(x)              T  "x y(x)

      Fj(c)            Fy(d)                 F  (j(e) ^ y(e))

    T(j(c)^y(c)    Tj(d)^y(d)            /          \

     T(j(c) )          Tj(d)                 F(j(e)     Fy(e)

      Ty(c)             Ty(d)                 Tj(e)       Ty(e)

        X                    X                      X               X

 

4.  F(j ^ $x(y(x) )  -> $x(j ^ y(x)

            T (j ^ $x(y(x) )

             F  $x(j ^ y(x)

              Tj

              T $x(y(x) )

              T y(c)

               F(j ^ y(c)   (x not free in j)

             /       \

         Fj         F y(c)

         X            X

 

7.  F( ¯$xj(x) -> "x¯j(x))

             T ¯$xj(x)

              F  "x¯j(x)

               F  ¯j(c)

                T  j(c)

              F $xj(x)

               Fj(c)

                 X

              

8.  F("x¯j(x) -> ¯$xj(x))

           T("x¯j(x))

            F(¯$xj(x))

             T $xj(x)

              Tj(c)

           T("x¯j(x))

           T¯j(c)

            Fj(c)

             X

 

 

9. . F($x¯j(x) -> ¯"xj(x))

           T($x¯j(x))

            F(¯"xj(x))

             T "xj(x)

              T¯j(c)

              Fj(c)

           T("xj(x))

           Tj(c)

              X

 

10.   F($x(j(x) -> y) -> ("xj(x) ->y)

            T($x(j(x) -> y)

             F("xj(x) ->y)

              T j(c) -> y  ( x not free in y)

               T"xj(x)

                F y

            /       \

        F j(c)     Ty

 T"xj(x)          X

    T j(c)

      X